This problem requires computing the minimum total seconds to make a mountain height zero given multiple workers with different speeds. You must consider simultaneous work and leverage binary search over the answer space to efficiently find the smallest feasible time. The solution combines array operations, math calculations, and greedy distribution checks for correctness.
Problem Statement
You are given an integer mountainHeight representing the height of a mountain and an array workerTimes where each element indicates the time in seconds a worker takes to reduce one unit of height. Multiple workers can work simultaneously, and each worker can work continuously until the mountain reaches zero.
Your task is to compute the minimum number of seconds required to reduce the mountain to zero height. The solution should account for all workers working together efficiently and use the optimal strategy to minimize the total time.
Examples
Example 1
Input: mountainHeight = 4, workerTimes = [2,1,1]
Output: 3
One way the height of the mountain can be reduced to 0 is: Since they work simultaneously, the minimum time needed is max(2, 3, 1) = 3 seconds.
Example 2
Input: mountainHeight = 10, workerTimes = [3,2,2,4]
Output: 12
The number of seconds needed is max(9, 12, 12, 12) = 12 seconds.
Example 3
Input: mountainHeight = 5, workerTimes = [1]
Output: 15
There is only one worker in this example, so the answer is workerTimes[0] + workerTimes[0] * 2 + workerTimes[0] * 3 + workerTimes[0] * 4 + workerTimes[0] * 5 = 15 .
Constraints
- 1 <= mountainHeight <= 105
- 1 <= workerTimes.length <= 104
- 1 <= workerTimes[i] <= 106
Solution Approach
Binary Search over Answer Space
Apply binary search on the range from 1 to a large upper bound representing maximum possible time. At each mid value, check if workers can collectively reduce the mountain to zero within that time. Narrow the range until the minimum feasible time is identified.
Check Feasibility with Greedy Distribution
For each candidate time, compute the total units each worker can remove and sum them. If the sum meets or exceeds mountainHeight, the candidate time is feasible. This greedy check ensures correctness while binary search efficiently narrows down the answer.
Optimize with Array and Math Operations
Precompute work contributions using math formulas to avoid repeated loops. Sort or prioritize workers if needed to reduce checks. Efficient array handling ensures the approach scales for large workerTimes arrays and high mountainHeight values.
Complexity Analysis
| Metric | Value |
|---|---|
| Time | Depends on the final approach |
| Space | Depends on the final approach |
Time complexity is O(n * log(maxTime)) where n is the number of workers and maxTime is the upper bound for binary search. Space complexity is O(1) extra if calculations are done in-place, otherwise O(n) for storing contributions.
What Interviewers Usually Probe
- Are you thinking about iterating over all possible seconds or can we use a smarter approach?
- Consider how the workers' different times affect the total reduction and feasibility check.
- Can you implement a binary search over the valid answer space instead of naive simulation?
Common Pitfalls or Variants
Common pitfalls
- Assuming sequential work instead of simultaneous worker contributions can overestimate time.
- Neglecting to check if total units reduced in candidate time meets the mountainHeight.
- Failing to set a sufficiently large upper bound for binary search may give incorrect results.
Follow-up variants
- Instead of finding minimum seconds, compute the maximum mountainHeight that can be reduced in a fixed number of seconds.
- Consider a version where workers have cooldown periods between units of work.
- Modify the problem to include varying efficiencies depending on current mountainHeight levels.
How GhostInterview Helps
- GhostInterview simulates candidate solutions and validates feasibility checks for each binary search step.
- It highlights common off-by-one errors in binary search and greedy sum calculations.
- The solver provides step-by-step reasoning for distributing work across workers efficiently.
Topic Pages
Related GhostInterview Pages
- LeetCode Interview Copilot - Use GhostInterview as a live solver when you want direct help with LeetCode-style coding questions.
- Coding Interview Assistant - See how GhostInterview supports array, string, linked list, graph, and tree interview workflows.
- How GhostInterview Works - Review the screenshot, reasoning, and answer flow before using the solver in a live interview.
FAQ
What is the best way to approach Minimum Number of Seconds to Make Mountain Height Zero?
Use binary search over the total time and verify feasibility with a greedy sum of worker contributions.
Can we solve this problem without binary search?
A naive simulation is possible but inefficient; binary search ensures optimal time complexity and handles large inputs.
How do workerTimes affect the solution?
Workers with smaller times can reduce more units per second, and the feasibility check must sum all contributions to meet mountainHeight.
What is a common mistake when implementing this solution?
Overlooking simultaneous work and summing contributions incorrectly can lead to wrong minimum seconds.
How does the binary search pattern apply here?
The pattern searches the smallest time where the combined work of all workers can reduce the mountainHeight to zero, efficiently narrowing the range.
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