To solve Minimum Operations to Make Character Frequencies Equal, compute character counts and explore frequency adjustments using state transition dynamic programming. The goal is to minimize deletions while ensuring all remaining characters occur the same number of times. Efficiently tracking frequency counts and applying optimal reductions yields the minimum operations required.
Problem Statement
You are given a string s consisting of lowercase English letters. A string is considered good if every character appears the same number of times. You may delete any character from s any number of times to achieve this.
Determine the minimum number of deletions required to make s a good string. Return an integer representing the least operations needed while ensuring all remaining character frequencies are equal.
Examples
Example 1
Input: s = "acab"
Output: 1
We can make s good by deleting one occurrence of character 'a' .
Example 2
Input: s = "wddw"
Output: 0
We do not need to perform any operations since s is initially good.
Example 3
Input: s = "aaabc"
Output: 2
We can make s good by applying these operations:
Constraints
- 3 <= s.length <= 2 * 104
- s contains only lowercase English letters.
Solution Approach
Count Character Frequencies
Use a hash table to count occurrences of each character. This allows quick access to frequency data, which forms the basis for dynamic programming decisions in adjusting counts.
Apply State Transition Dynamic Programming
Sort unique frequencies and iterate over possible target frequencies. For each character, compute the cost to reduce its count to match the target frequency, using DP to track minimal deletions across all choices.
Select Minimum Deletion Configuration
Evaluate all computed DP states and select the configuration with the lowest total deletions. This ensures all characters in the resulting string occur the same number of times with minimal operations.
Complexity Analysis
| Metric | Value |
|---|---|
| Time | Depends on the final approach |
| Space | Depends on the final approach |
Time complexity depends on the number of unique character frequencies and DP state transitions, roughly O(n log n) for counting and sorting plus frequency adjustment iterations. Space complexity is dominated by hash table storage and DP table, typically O(n) for character counts.
What Interviewers Usually Probe
- Look for correct use of hash table to tally character frequencies.
- Check if candidate properly applies dynamic programming for state transitions between frequency reductions.
- Assess awareness of trade-offs between deleting excess characters versus leaving frequencies uneven.
Common Pitfalls or Variants
Common pitfalls
- Failing to account for multiple characters sharing the same frequency, leading to incorrect minimal deletions.
- Overcomplicating the DP by considering unnecessary permutations of character deletions.
- Neglecting edge cases where all characters already have equal frequency, resulting in extra operations.
Follow-up variants
- Modify the problem to allow incrementing character counts instead of only deletions.
- Restrict the string to only vowels and optimize deletions to equalize their frequencies.
- Introduce a maximum allowed deletion limit and find if making frequencies equal is possible under that constraint.
How GhostInterview Helps
- Provides step-by-step guidance in setting up frequency counts and DP tables for this exact problem.
- Highlights efficient strategies to reduce state space when exploring frequency adjustments.
- Identifies edge cases and minimal operation scenarios, ensuring the solution handles all character distributions.
Topic Pages
Related GhostInterview Pages
- LeetCode Interview Copilot - Use GhostInterview as a live solver when you want direct help with LeetCode-style coding questions.
- Coding Interview Assistant - See how GhostInterview supports array, string, linked list, graph, and tree interview workflows.
- How GhostInterview Works - Review the screenshot, reasoning, and answer flow before using the solver in a live interview.
FAQ
What is the main idea behind solving Minimum Operations to Make Character Frequencies Equal?
The key idea is to compute character frequencies and use dynamic programming to minimize deletions required to make all frequencies equal.
Do I need to consider the order of characters in the string?
No, the order is irrelevant; only the counts of each character matter for determining minimal deletions.
Can this approach handle large strings efficiently?
Yes, using hash tables for frequency counting and DP for state transitions ensures efficiency even for strings up to length 2 * 10^4.
Are there alternative methods besides dynamic programming?
Greedy strategies exist but may fail on some distributions; state transition DP guarantees minimal deletions for all cases.
How do I verify my solution is minimal?
Check all possible target frequencies and confirm that the computed deletion count matches the lowest total possible across all DP states.
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