The problem requires replacing '?' characters in a string to minimize the associated cost. Greedily choose the smallest lexicographical characters while ensuring the sum of cost(i) for all indices remains minimized. A combination of greedy algorithms, hash tables, and invariant validation is key to solving this problem efficiently.
Problem Statement
You are given a string s, where each character is either a lowercase English letter or a '?'. Your goal is to replace all '?' characters with lowercase letters to minimize the value of the string. The value of the string is determined by the sum of cost(i) for all indices i. For a string t, the cost(i) at an index i is the number of occurrences of t[i] in the substring t[0..i-1].
You need to find the lexicographically smallest string that minimizes the total cost. Specifically, you are tasked with replacing '?' characters in a way that ensures the resulting string has the minimal cost, while keeping the overall structure as lexicographically small as possible. Be mindful of the fact that cost(i) depends on previous occurrences of characters and will influence future choices.
Examples
Example 1
Input: s = "???"
Output: "abc"
In this example, we can replace the occurrences of '?' to make s equal to "abc" . For "abc" , cost(0) = 0 , cost(1) = 0 , and cost(2) = 0 . The value of "abc" is 0 . Some other modifications of s that have a value of 0 are "cba" , "abz" , and, "hey" . Among all of them, we choose the lexicographically smallest.
Example 2
Input: s = "a?a?"
Output: "abac"
In this example, the occurrences of '?' can be replaced to make s equal to "abac" . For "abac" , cost(0) = 0 , cost(1) = 0 , cost(2) = 1 , and cost(3) = 0 . The value of "abac" is 1 .
Constraints
- 1 <= s.length <= 105
- s[i] is either a lowercase English letter or '?'.
Solution Approach
Greedy Choice
To minimize the cost, greedily replace each '?' with the lexicographically smallest valid character. This ensures that no extra penalties are incurred from previous choices while minimizing cost.
Invariant Validation
As you replace each '?' character, check that the cost is minimized by ensuring no previously chosen characters repeat excessively. This validation helps in maintaining a minimal cost across the entire string.
Efficient Counting with Hash Table
Use a hash table to track the frequency of characters already in the string. This allows efficient lookup and ensures that characters are selected based on their frequency, which directly affects the cost calculation.
Complexity Analysis
| Metric | Value |
|---|---|
| Time | Depends on the final approach |
| Space | Depends on the final approach |
The time and space complexity depend on the approach you choose. A naive solution might lead to O(n^2) due to repeated counting. However, with efficient hashing and careful greedy choices, the complexity can be reduced to O(n).
What Interviewers Usually Probe
- Does the candidate demonstrate understanding of greedy algorithms and their application to string problems?
- Is the candidate able to explain how the cost function influences their decision-making process?
- How effectively does the candidate use hash tables to minimize cost while ensuring lexicographical order?
Common Pitfalls or Variants
Common pitfalls
- Misunderstanding the cost calculation and how previous characters influence the current cost.
- Failing to consider the lexicographical order of the string while replacing '?' characters.
- Overcomplicating the solution by not utilizing hash tables efficiently for counting character occurrences.
Follow-up variants
- Change the problem to handle a larger character set, such as including uppercase letters or digits.
- Introduce a limit on the number of distinct characters allowed in the string.
- Allow multiple valid outputs with the same cost but ask for the lexicographically largest string.
How GhostInterview Helps
- GhostInterview helps by guiding you through a step-by-step approach to understand how greedy algorithms minimize cost while maintaining lexicographical order.
- The platform provides immediate feedback on your choices, helping you debug any missteps in counting or character selection.
- With practice problems and tailored hints, GhostInterview helps you perfect the application of hash tables and greedy choices to solve complex string problems.
Topic Pages
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- LeetCode Interview Copilot - Use GhostInterview as a live solver when you want direct help with LeetCode-style coding questions.
- Coding Interview Assistant - See how GhostInterview supports array, string, linked list, graph, and tree interview workflows.
- How GhostInterview Works - Review the screenshot, reasoning, and answer flow before using the solver in a live interview.
FAQ
How can I minimize the cost of the string in the 'Replace Question Marks in String to Minimize Its Value' problem?
To minimize the cost, replace '?' with the smallest lexicographical character while maintaining invariant validation to ensure previous characters don't repeat excessively.
What is the time complexity of solving the 'Replace Question Marks in String to Minimize Its Value' problem?
The time complexity depends on the approach but can be optimized to O(n) by using a hash table for frequency counting and greedy character selection.
What is the role of the hash table in solving the 'Replace Question Marks in String to Minimize Its Value' problem?
A hash table tracks the frequency of characters already in the string, allowing efficient character replacement and ensuring minimal cost without excessive repetition.
Can there be multiple valid solutions for this problem?
Yes, there can be multiple valid solutions with the same minimum cost. However, the lexicographically smallest solution is preferred.
What is the greedy approach used in the 'Replace Question Marks in String to Minimize Its Value' problem?
The greedy approach involves choosing the lexicographically smallest valid character to replace '?' in each step, ensuring the minimal cost at each stage of the string.
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