To solve Reverse Integer efficiently, extract digits one by one and build the reversed number while checking for 32-bit overflow. Handle negative numbers by preserving the sign and immediately returning 0 if reversing causes an overflow. This approach uses constant space and logarithmic time relative to the number of digits.
Problem Statement
Given a signed 32-bit integer x, return its digits reversed. If the reversed value exceeds the 32-bit signed integer range [-2^31, 2^31 - 1], return 0. The environment does not support storing 64-bit integers.
For example, reversing 123 yields 321, reversing -123 yields -321, and reversing 120 yields 21. Implement a solution that carefully handles overflow and negative inputs while following a math-driven approach.
Examples
Example 1
Input: x = 123
Output: 321
Example details omitted.
Example 2
Input: x = -123
Output: -321
Example details omitted.
Example 3
Input: x = 120
Output: 21
Example details omitted.
Constraints
- -231 <= x <= 231 - 1
Solution Approach
Digit Extraction with Overflow Check
Iteratively extract the last digit using modulo 10, append it to a reversed number, and check if appending will exceed 32-bit bounds before each step. Stop and return 0 on potential overflow.
Sign Preservation
Maintain the sign of the original number by multiplying the reversed digits by -1 if the original number is negative. Ensure that negative overflow is also checked.
Constant Space Implementation
Avoid using arrays or string conversions to store intermediate digits. Build the reversed number incrementally using only integer arithmetic to achieve O(1) space complexity.
Complexity Analysis
| Metric | Value |
|---|---|
| Time | O(\log(x)) |
| Space | O(1) |
Reversing digits requires processing each digit once, resulting in O(log(x)) time since the number of digits in x is proportional to log10(x). Space remains O(1) because no extra storage is needed beyond a few integer variables.
What Interviewers Usually Probe
- Expect discussion about handling overflow conditions explicitly.
- Clarify whether negative numbers should retain their sign after reversal.
- Look for solutions that avoid converting integers to strings.
Common Pitfalls or Variants
Common pitfalls
- Failing to check for 32-bit overflow before updating the reversed number.
- Incorrectly handling negative integers or losing the negative sign.
- Using string conversion which may exceed memory constraints or bypass math-driven strategy.
Follow-up variants
- Reversing digits in a 64-bit integer while ensuring 64-bit overflow is handled.
- Counting how many digits can be reversed before reaching overflow.
- Reversing only the even or odd digits of a number while preserving their positions.
How GhostInterview Helps
- Provides a step-by-step breakdown for extracting digits and detecting overflow safely.
- Highlights the negative number edge cases and overflow failure modes for accurate solutions.
- Offers practice implementing the math-driven reversal using constant space and iterative logic.
Topic Pages
Related GhostInterview Pages
- LeetCode Interview Copilot - Use GhostInterview as a live solver when you want direct help with LeetCode-style coding questions.
- Coding Interview Assistant - See how GhostInterview supports array, string, linked list, graph, and tree interview workflows.
- How GhostInterview Works - Review the screenshot, reasoning, and answer flow before using the solver in a live interview.
FAQ
What is the best way to reverse an integer without causing overflow?
Extract digits one at a time using modulo and division, build the reversed number incrementally, and check for overflow before each append.
How do I handle negative integers in Reverse Integer?
Preserve the sign of the original number, multiply the reversed digits by -1, and ensure negative overflow checks are applied.
Can I convert the integer to a string to reverse it?
Using strings bypasses the math-driven pattern and may violate space constraints; integer arithmetic is preferred for GhostInterview solutions.
What is the time complexity of the Reverse Integer solution?
Time complexity is O(log(x)) since each digit is processed once, where the number of digits is proportional to log10(x).
Why is checking for overflow before appending each digit important?
Appending without checking can silently exceed 32-bit limits, causing incorrect results or undefined behavior in a math-driven integer reversal.
Need direct help with Reverse Integer instead of spending more time grinding it?
Download GhostInterview when you want a LeetCode solver, not another long practice loop. Capture Reverse Integer from a screenshot, get the answer path and complexity, and use supported stealth workflows that stay outside captured layers.
Capture the prompt fast instead of rewriting the problem by hand.
Get the solution path, trade-offs, and complexity summary in one pass.
Stay outside captured layers on supported screen-share workflows.
Stay in the same pattern family
Determine if a given integer reads the same forward and backward using a math-driven solution strategy without converting to string.
Open problem page#2 Add Two NumbersAdd Two Numbers requires careful linked-list pointer manipulation to sum digits while handling carries efficiently in interview settings.
Open problem page#12 Integer to RomanConvert a given integer to its Roman numeral representation using hash table mapping and decimal place math operations efficiently.
Open problem page