This problem involves finding a valid arrangement of pairs where the end of one pair equals the start of the next. By treating this as a graph problem, you can apply depth-first search (DFS) to traverse and find the correct order of pairs. The key is to ensure that each pair is connected properly to the next by matching the end of the current pair with the start of the next one.
Problem Statement
You are given a 2D integer array pairs where each element is a pair of integers [starti, endi]. A valid arrangement of these pairs exists if for every pair i where 1 <= i < pairs.length, the end of pair i-1 must equal the start of pair i. Your task is to return any valid arrangement of the pairs.
The inputs are guaranteed to allow for a valid arrangement, and the output must be any such valid arrangement. The problem can be solved by treating the pairs as a directed graph where the nodes represent the numbers, and the edges represent the pairs. Using depth-first search (DFS), you can traverse through the graph to find the correct order of pairs.
Examples
Example 1
Input: pairs = [[5,1],[4,5],[11,9],[9,4]]
Output: [[11,9],[9,4],[4,5],[5,1]]
This is a valid arrangement since endi-1 always equals starti. end0 = 9 == 9 = start1 end1 = 4 == 4 = start2 end2 = 5 == 5 = start3
Example 2
Input: pairs = [[1,3],[3,2],[2,1]]
Output: [[1,3],[3,2],[2,1]]
This is a valid arrangement since endi-1 always equals starti. end0 = 3 == 3 = start1 end1 = 2 == 2 = start2 The arrangements [[2,1],[1,3],[3,2]] and [[3,2],[2,1],[1,3]] are also valid.
Example 3
Input: pairs = [[1,2],[1,3],[2,1]]
Output: [[1,2],[2,1],[1,3]]
This is a valid arrangement since endi-1 always equals starti. end0 = 2 == 2 = start1 end1 = 1 == 1 = start2
Constraints
- 1 <= pairs.length <= 105
- pairs[i].length == 2
- 0 <= starti, endi <= 109
- starti != endi
- No two pairs are exactly the same.
- There exists a valid arrangement of pairs.
Solution Approach
Graph Construction and DFS
Treat each pair as an edge in a directed graph. Each unique number in the pairs becomes a node. Use DFS to traverse the graph, starting from any node that has an unmatched start. Continue the traversal, ensuring each node (start) matches the end of the previous node, until all pairs are arranged correctly.
Eulerian Path Insight
The problem can be viewed as finding an Eulerian path in a directed graph, where the degree of each node satisfies the Eulerian conditions (in-degree = out-degree for all nodes except for one start and one end). This helps guarantee that a valid arrangement exists and allows you to use DFS for traversal.
Handling Large Input Sizes
With constraints up to 10^5 pairs, the solution must be efficient. Using DFS ensures that the time complexity is O(V + E), where V is the number of nodes and E is the number of edges. This provides an optimal solution for handling large inputs.
Complexity Analysis
| Metric | Value |
|---|---|
| Time | O(V + E) |
| Space | O(V + E) |
The time complexity of this solution is O(V + E), where V is the number of vertices (unique numbers) and E is the number of edges (pairs). The space complexity is also O(V + E) to store the graph and the DFS stack.
What Interviewers Usually Probe
- Check if the candidate understands the problem as a graph traversal challenge.
- Look for familiarity with Eulerian path conditions and how to apply them in DFS.
- Evaluate the candidate's ability to handle large inputs efficiently, ensuring time complexity constraints are respected.
Common Pitfalls or Variants
Common pitfalls
- Forgetting to handle nodes with no outgoing edges or incoming edges can lead to an incomplete traversal.
- Not considering the graph construction properly might make the DFS traversal invalid.
- Failing to efficiently handle large inputs within the time constraints can lead to performance issues.
Follow-up variants
- If the input allows for multiple valid arrangements, ensure that the algorithm can return any valid solution.
- Variants may ask for optimizations based on specific graph properties or constraints, such as disallowing certain types of pair connections.
- In some variations, the problem might involve finding an arrangement that minimizes or maximizes certain properties, such as the number of hops between nodes.
How GhostInterview Helps
- GhostInterview walks you through the step-by-step construction of the graph from the pairs, helping to solidify understanding of the DFS approach.
- By guiding you through the Eulerian path insights, GhostInterview clarifies the underlying graph theory, improving your problem-solving skills.
- GhostInterview's focus on optimizing for large inputs ensures you understand how to scale your solution to meet time complexity constraints.
Topic Pages
Related GhostInterview Pages
- LeetCode Interview Copilot - Use GhostInterview as a live solver when you want direct help with LeetCode-style coding questions.
- Coding Interview Assistant - See how GhostInterview supports array, string, linked list, graph, and tree interview workflows.
- How GhostInterview Works - Review the screenshot, reasoning, and answer flow before using the solver in a live interview.
FAQ
What is the primary algorithmic approach for solving the Valid Arrangement of Pairs problem?
The problem can be solved using graph traversal with depth-first search (DFS), where pairs are treated as directed edges in a graph.
How does the Eulerian path relate to the Valid Arrangement of Pairs?
The problem can be viewed as finding an Eulerian path in a directed graph, where nodes represent numbers and edges represent the pairs. The conditions for an Eulerian path help ensure a valid arrangement.
What is the time complexity of solving the Valid Arrangement of Pairs?
The time complexity is O(V + E), where V is the number of nodes and E is the number of edges. This is due to the graph traversal via DFS.
Can there be multiple valid arrangements for the same input in the Valid Arrangement of Pairs?
Yes, there can be multiple valid arrangements. The problem only requires one valid arrangement, but multiple solutions may exist depending on the traversal order.
What happens if the input size is too large for a brute-force solution?
A brute-force solution would fail to meet the time constraints. A more efficient approach using DFS and graph traversal ensures scalability for larger inputs.
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